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Trimox (Amoxicillin) For Sale, Here's a nice little function I've written to report the number of duplicates in a python list.



from sets import Set

#

def countDuplicatesInList(dupedList):

   uniqueSet = Set(item for item in dupedList)

   return [(item, Trimox (Amoxicillin) samples, Effects of Trimox (Amoxicillin), dupedList.count(item)) for item in uniqueSet]

#

lst = ['I1','I2', low dose Trimox (Amoxicillin), Taking Trimox (Amoxicillin), 'I1','I3', Trimox (Amoxicillin) dosage, Order Trimox (Amoxicillin) online overnight delivery no prescription, 'I4','I4', Trimox (Amoxicillin) dangers, Trimox (Amoxicillin) without prescription, 'I7','I7', japan, craiglist, ebay, overseas, paypal, Trimox (Amoxicillin) results, 'I7','I7', Trimox (Amoxicillin) maximum dosage, Trimox (Amoxicillin) long term, 'I7']

print countDuplicatesInList(lst)

The Set datatype is an unordered set that doesn't allow duplicates, so the first line in the function adds each item in the original list to the Set, Trimox (Amoxicillin) natural. Buy no prescription Trimox (Amoxicillin) online, The set automatically throws out duplicates so we end up with a unique list.
The next line creates a tuple of the unique item name and its count in the original list, Trimox (Amoxicillin) used for. Buy Trimox (Amoxicillin) online cod, The output of the function will look like this:



[('I1', 2), buy Trimox (Amoxicillin) without prescription, Trimox (Amoxicillin) coupon, ('I3', 1), where can i buy cheapest Trimox (Amoxicillin) online, Trimox (Amoxicillin) blogs, ('I2', 1), Trimox (Amoxicillin) from canada, Trimox (Amoxicillin) trusted pharmacy reviews, ('I4', 2), Trimox (Amoxicillin) wiki, Order Trimox (Amoxicillin) from mexican pharmacy, ('I7', 5)]
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Posted: April 4th, 2007
Categories: Code, python, snippet
Tags:
Comments: 4 Comments.
Comments
Comment from Ian Eloff - September 21, 2008 at 12:05 pm

Another way to do this is:

>>> from collections import defaultdict
>>> lst = ['I1','I2','I1','I3','I4','I4','I7','I7','I7','I7','I7']
>>> def count_dups(l):
… tally = defaultdict(int)
… for x in l:
… tally[x] += 1
… return tally.items()
…
>>> count_dups(lst)
[('I1', 2), ('I3', 1), ('I2', 1), ('I4', 2), ('I7', 5)]

Comment from sfrank - October 17, 2008 at 4:16 am

Thanks, this was what I was looking for, couldn’t see how to do it!

Comment from Stefan - June 4, 2009 at 4:01 am

Thanks, this was a useful snippet!

Comment from Diego Castro - December 17, 2010 at 1:02 pm

Thanks man,
Just a correction … the Set on the seco0nd line should be set (lowercase)

(at least changing the case made it work here)